(N/A) For a uniformly charged spherical shell of radius $R$ and total charge $Q$:
$1$. Inside the shell $(r < R)$,the electric field is zero,so the potential is constant and equal to the potential at the surface: $V = \frac{1}{4\pi\epsilon_0} \frac{Q}{R}$.
$2$. On the surface $(r = R)$,the potential is $V = \frac{1}{4\pi\epsilon_0} \frac{Q}{R}$.
$3$. Outside the shell $(r > R)$,the shell behaves like a point charge at the center,so the potential varies as $V \propto \frac{1}{r}$,specifically $V = \frac{1}{4\pi\epsilon_0} \frac{Q}{r}$.
The graph shows a constant potential line for $r \leq R$ and a hyperbolic decay curve for $r > R$.