The distances of the point (1, 2, 3) from the | vedclass

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(B) The distance of a point $P(x, y, z)$ from the coordinate axes is given by:$1$. Distance from the $x$-axis: $d_x = \sqrt{y^2 + z^2} = \sqrt{2^2 + 3

Vedclass · Accepted Answer

$\sqrt{13}, \sqrt{10}, \sqrt{5}$

Vedclass · Answer

(B) The distance of a point $P(x, y, z)$ from the coordinate axes is given by:$1$. Distance from the $x$-axis: $d_x = \sqrt{y^2 + z^2} = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13}$.$2$. Distance from the $y$-axis: $d_y = \sqrt{x^2 + z^2} = \sqrt{1^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10}$.$3$. Distance from the $z$-axis: $d_z = \sqrt{x^2 + y^2} = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5}$.Thus,the distances are $\sqrt{13}, \sqrt{10}, \sqrt{5}$.

The distances of the point $(1, 2, 3)$ from the coordinate axes are:

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