The distance between the two parallel lines y | vedclass

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(C) The given equations of the parallel lines are $2x - y + 7 = 0$ and $2x - y + 5 = 0$.Comparing these with the standard form $Ax + By + C_1 = 0$ and

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$\frac{2}{\sqrt{5}}$

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(C) The given equations of the parallel lines are $2x - y + 7 = 0$ and $2x - y + 5 = 0$.Comparing these with the standard form $Ax + By + C_1 = 0$ and $Ax + By + C_2 = 0$,we have $A = 2$,$B = -1$,$C_1 = 7$,and $C_2 = 5$.The formula for the distance $d$ between two parallel lines is given by $d = \frac{|C_1 - C_2|}{\sqrt{A^2 + B^2}}$.Substituting the values,we get $d = \frac{|7 - 5|}{\sqrt{2^2 + (-1)^2}}$.$d = \frac{2}{\sqrt{4 + 1}} = \frac{2}{\sqrt{5}}$.

The distance between the two parallel lines $y = 2x + 7$ and $y = 2x + 5$ is:

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