The differential equation whose solution is y | vedclass

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Question

(B) Given the equation $y = cx + c - c^3$. To find the differential equation,we differentiate the given equation with respect to $x$: $\frac{dy}{dx} =

Vedclass · Accepted Answer

$y = x\frac{dy}{dx} + \frac{dy}{dx} - \left(\frac{dy}{dx}\right)^3$

Vedclass · Answer

(B) Given the equation $y = cx + c - c^3$. To find the differential equation,we differentiate the given equation with respect to $x$: $\frac{dy}{dx} = c$. Now,we substitute $c = \frac{dy}{dx}$ back into the original equation $y = cx + c - c^3$: $y = x\left(\frac{dy}{dx}\right) + \frac{dy}{dx} - \left(\frac{dy}{dx}\right)^3$. Thus,the required differential equation is $y = x\frac{dy}{dx} + \frac{dy}{dx} - \left(\frac{dy}{dx}\right)^3$.

The differential equation whose solution is $y = cx + c - c^3$ is:

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