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(D) The power dissipated in a circuit with a constant current $I$ is given by $P = I^2 R_{eq}$,where $R_{eq}$ is the equivalent resistance.Since $I$ i

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$P_C < P_B < P_A < P_D$

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(D) The power dissipated in a circuit with a constant current $I$ is given by $P = I^2 R_{eq}$,where $R_{eq}$ is the equivalent resistance.Since $I$ is the same for all circuits,$P$ is directly proportional to $R_{eq}$ $(P \propto R_{eq})$.Let's calculate the equivalent resistance for each circuit:$(A)$ Two resistors in parallel $(R/2)$ in series with one resistor $(R)$: $R_A = R/2 + R = 1.5R$.$(B)$ Two resistors in series $(2R)$ in parallel with one resistor $(R)$: $R_B = (2R \cdot R) / (2R + R) = 2R/3 \approx 0.67R$.$(C)$ Three resistors in parallel: $R_C = R/3 \approx 0.33R$.$(D)$ Three resistors in series: $R_D = R + R + R = 3R$.Comparing the equivalent resistances: $R_C (0.33R) Therefore,the increasing order of power dissipation is $P_C < P_B < P_A < P_D$.

Different combinations of $3$ resistors of equal resistance $R$ are shown in the figures. The increasing order for power dissipation is:

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