Derive the formula for the electric potential energy of system of three charges.
Derive the formula for the electric potential energy of system of three charges.
Let charge $q_{1}, q_{2}$ and $q_{3}$ are bring from infinity distance to at the point $\mathrm{P}_{1}, \mathrm{P}_{2}$ and $\mathrm{P}_{3}$ located at distance $r_{1}, r_{2}$ and $r_{3}$ respectively.
All three charges are brought as shown in figure.
To bring $q_{1}$ first from infinity to $\mathrm{P}_{1}$, the work done $\mathrm{W}_{1}=0$ $.....1$
because there is no external force to bring $q_{1}$ to $\mathrm{P}_{1}$ Electric potential at $\mathrm{P}_{2}$ due to charge $q_{1}$,
$\mathrm{V}_{1}=\frac{k q_{1}}{r_{12}}$
... $(2)$
Now work done to bring charge $q_{2}$ at point $\mathrm{P}_{2}$,
$\mathrm{W}_{2}=\mathrm{V}_{1} \times q_{2}$
$\therefore \mathrm{W}_{2}=\frac{k q_{1} q_{2}}{r_{12}}$$.....3$
Electric potential at $\mathrm{P}_{3}$ due to charge $q_{1}+q_{2}$, $\mathrm{V}_{2}=\frac{k q_{1}}{r_{13}}+\frac{k q_{2}}{r_{23}}$
$\therefore$ Work done to bring charge $q_{3}$ to $\mathrm{P}_{3}$
$\mathrm{W}_{3}=$ potential at $\mathrm{P}_{3}$ due to $q_{1}+q_{2} \times q_{3}$ charge
$=k\left[\frac{q_{1}}{r_{13}}+\frac{q_{2}}{r_{23}}\right] \times q_{3}$
$\quad=k\left[\frac{q_{1} q_{3}}{r_{13}}+\frac{q_{2} q_{3}}{r_{23}}\right]$$.....4$
$\therefore$ Total potential energy of charges $q_{1}+q_{2}+q_{3}$ $\mathrm{U}=\mathrm{W}_{1}+\mathrm{W}_{2}+\mathrm{W}_{3}$ $\mathrm{U}=\mathrm{W}_{1}+\mathrm{W}_{2}+\mathrm{W}_{3}$
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