Dehydrogenation of CH_3-CH(OH)-CH_3 gives | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Dehydrogenation of a secondary alcohol like isopropyl alcohol $(CH_3-CH(OH)-CH_3)$ involves the removal of hydrogen in the presence of a catalyst

Vedclass · Accepted Answer

Acetone

Vedclass · Answer

(A) Dehydrogenation of a secondary alcohol like isopropyl alcohol $(CH_3-CH(OH)-CH_3)$ involves the removal of hydrogen in the presence of a catalyst like copper at $573 \ K$. The reaction is: $CH_3-CH(OH)-CH_3 \xrightarrow{Cu, 573 \ K} CH_3-CO-CH_3 + H_2$. This results in the formation of a ketone,which is acetone $(CH_3-CO-CH_3)$.

Dehydrogenation of $CH_3-CH(OH)-CH_3$ gives

Similar Questions

Correct statement$(s)$ in cases of $n-$butanol and $t-$butanol is (are)

The rate of the esterification reaction between $R-OH$ and $p-nitrobenzoic$ acid will be fastest when $R$ is:

The major product obtained by the dehydration of the given alcohol is $:-$

$CH_3-C(CH_3)_2-Cl$ $\xrightarrow{NaCN} A$ $\xrightarrow{dil. H_2SO_4} B$. Compound $B$ is:

In the given reaction,$[X]$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module