Correct statement(s) in cases of n-butanol an | vedclass

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(B, C) $n-$butanol is a straight-chain alcohol,while $t-$butanol is a branched-chain alcohol.Branching decreases the surface area of the molecule,whic

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boiling point of $t-$butanol is lower than $n-$butanol

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(B, C) $n-$butanol is a straight-chain alcohol,while $t-$butanol is a branched-chain alcohol.Branching decreases the surface area of the molecule,which reduces the strength of intermolecular van der Waals forces,leading to a lower boiling point for $t-$butanol compared to $n-$butanol.Additionally,branching increases the solubility of alcohols in water because it reduces the hydrophobic character of the alkyl group.Therefore,$t-$butanol is more soluble in water and has a lower boiling point than $n-$butanol.Thus,both statements $B$ and $C$ are correct.

Correct statement$(s)$ in cases of $n-$butanol and $t-$butanol is (are)

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