Define 'average speed'. An object moves with a uniform speed of $10\, m s ^{-1}$ for $5 s$ and then with a uniform speed of $5\, m s ^{-1}$ for $10\, s$. Find its average speed.
Average speed of an object is obtained by dividing the total distance travelled by the total time taken.
Total distance covered $=(10 \times 5+5 \times 10) m$
Time taken $=15 s$
Therefore, Average speed $=\frac{100 m }{15 s }=6.66 m s ^{-1}$
The area under the velocity$-$time graph gives the value of
Four cars $A$, $B$, $C$ and $D$ are moving on a levelled road. Their distance versus time graphs are shown in Fig. Choose the correct statement
Distinguish between terms distance and displacement.
$(a)$ Differentiate between speed and velocity.
$(b)$ When is a body said to have uniform velocity ?
$(c)$ How can we describe the position of an object ? Illustrate with suitable example.
Two cars $A$ and $B$ have their displacement$-$time graph as given below. Which car has a greater velocity ?