Decarboxylation of sodium salicylate with soda lime forms

$A$ compound $A$ $(C_{7}H_{8}O)$ is insoluble in $NaHCO_{3}$ solution but dissolves in $NaOH$ and gives a characteristic colour with neutral $FeCl_{3}$ solution. When treated with bromine water,compound $A$ forms the compound $B$ with the formula $C_{7}H_{5}OBr_{3}$. $A$ is:

The increasing order of acidity among phenol,$p-$methylphenol,$m-$nitrophenol and $p-$nitrophenol is

Match the reagents in List-$I$ with the product in List-$II$ obtained from phenol.

List-$I$	List-$II$
$a$. $(i)$ $NaOH$,$(ii)$ $CO_2$,$(iii)$ $H^{+}$	$i$. Benzoquinone
$b$. $(i)$ Aqueous $NaOH + CHCl_3$,$(ii)$ $H^{+}$	$ii$. Benzene
$c$. $Zn$ dust,$\Delta$	$iii$. Salicylaldehyde
$d$. $Na_2Cr_2O_7, H_2SO_4$	$iv$. Salicylic acid

Choose the correct answer from the options given below:

For the given reaction,identify the major products $A$ and $B$ respectively.

$C_6H_5OH \xrightarrow[Br_2]{OH^{\ominus}} ; $ Intermediate of the given reaction is/are