Cupric compounds are more stable than their c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electronic configurations of cuprous $(Cu^{+})$ and cupric $(Cu^{2+})$ ions are as follows:$Cu^{+} = [Ar] 3d^{10} 4s^{0}$$Cu^{2+} = [Ar] 3d^{9

Vedclass · Accepted Answer

the lattice energy released for cupric compounds is much higher than for cuprous compounds

Vedclass · Answer

(D) The electronic configurations of cuprous $(Cu^{+})$ and cupric $(Cu^{2+})$ ions are as follows:$Cu^{+} = [Ar] 3d^{10} 4s^{0}$$Cu^{2+} = [Ar] 3d^{9} 4s^{0}$Although $Cu^{+}$ has a more stable electronic configuration,$Cu^{2+}$ compounds are more stable in the solid state.This is primarily because the $2^{nd}$ ionization potential $(IP)$ of $Cu$ is not sufficiently high to prevent the formation of $Cu^{2+}$,and the higher charge density of $Cu^{2+}$ leads to a significantly higher lattice energy in ionic compounds compared to $Cu^{+}$ compounds.This large release of lattice energy compensates for the energy required to remove the second electron.

List-$I$ (Element)	List-$II$ (Block)
$(A)$ $Ra$	$(I)$ $p$-block
$(B)$ $Uuq$	$(II)$ $s$-block
$(C)$ $Ds$	$(III)$ $f$-block
$(D)$ $Fm$	$(IV)$ $d$-block

Cupric compounds are more stable than their cuprous counterparts in the solid state. This is because

Similar Questions

Which of the following statements is incorrect?

The valence shell electronic configuration of $Cr$ and $Cu$ atoms,respectively,are

Match the following:
List-$I$ (Element) List-$II$ (Block)
$(A)$ $Ra$ $(I)$ $p$-block
$(B)$ $Uuq$ $(II)$ $s$-block
$(C)$ $Ds$ $(III)$ $f$-block
$(D)$ $Fm$ $(IV)$ $d$-block

The correct answer is

Which of the following oxides has the maximum basicity?

Which elements of the $3d$ series do not show variable valency?

Vedclass Test Series

Exam Paper Generator

Online Exam Module