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(B) The atomic number of $Cr$ is $24$. Its expected configuration is $3 \ d^4 4 \ s^2$,but due to the extra stability of half-filled $d$-orbitals,it b

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$3 \ d^5 4 \ s^1 ; 3 \ d^{10} 4 \ s^1$

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(B) The atomic number of $Cr$ is $24$. Its expected configuration is $3 \ d^4 4 \ s^2$,but due to the extra stability of half-filled $d$-orbitals,it becomes $3 \ d^5 4 \ s^1$.The atomic number of $Cu$ is $29$. Its expected configuration is $3 \ d^9 4 \ s^2$,but due to the extra stability of completely-filled $d$-orbitals,it becomes $3 \ d^{10} 4 \ s^1$.Therefore,the correct configuration is $3 \ d^5 4 \ s^1$ and $3 \ d^{10} 4 \ s^1$.

The valence shell electronic configuration of $Cr$ and $Cu$ atoms,respectively,are

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