Correct statements for the given reaction are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction involves the deprotonation of squaric acid $(A)$ by $2$ equivalents of $OH^-$ to form the squarate dianion $(B)$.$1$. Compound '$B$'

Vedclass · Accepted Answer

$A, C$ and $D$ only

Vedclass · Answer

(D) The reaction involves the deprotonation of squaric acid $(A)$ by $2$ equivalents of $OH^-$ to form the squarate dianion $(B)$.$1$. Compound '$B$' (squarate dianion) is aromatic because it is cyclic,planar,fully conjugated,and contains $6 \pi$ electrons ($4n+2$ rule,where $n=1$). Thus,statement $A$ is correct.$2$. The reaction is an acid-base reaction involving the removal of acidic protons from squaric acid. Acid-base reactions are typically very fast,not slow. Thus,statement $B$ is incorrect.$3$. Compound '$A$' (squaric acid) contains an enol group adjacent to a carbonyl group,which allows it to exhibit keto-enol tautomerism. Thus,statement $C$ is correct.$4$. Due to resonance in the squarate dianion $(B)$,the negative charge is delocalized over the entire ring,making all $C-C$ bond lengths equal. Thus,statement $D$ is correct.Therefore,statements $A, C,$ and $D$ are correct.

Correct statements for the given reaction are :
$A$. Compound '$B$' is aromatic
$B$. The completion of above reaction is very slow
$C$. '$A$' shows tautomerism
$D$. The bond lengths $C-C$ in compound $B$ are found to be same
Choose the correct answer from the options given below :

Similar Questions

Shown below is the structure of methyl acetate with three different $\alpha, \beta$ and $\gamma$ carbon-oxygen bonds.
The correct order of bond lengths of these bonds is:

Among the following structures,the one which is not a resonating structure of others is:

Identify the compound in which steric inhibition of resonance is present.

Draw other resonance structures related to the following structure and find out whether the functional group present in the molecule is ortho,para directing or meta directing.

The correct order of $C=O$ bond length in ethyl propanoate $(I)$,ethyl propenoate $(II)$ and ethenyl propanoate $(III)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Correct statements for the given reaction are :$A$. Compound '$B$' is aromatic$B$. The completion of above reaction is very slow$C$. '$A$' shows tautomerism$D$. The bond lengths $C-C$ in compound $B$ are found to be sameChoose the correct answer from the options given below :