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(A) To find the maximum and minimum values of the objective function $F = 4x + 6y$,we evaluate $F$ at each corner point of the feasible region:$1$. At

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$60$

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(A) To find the maximum and minimum values of the objective function $F = 4x + 6y$,we evaluate $F$ at each corner point of the feasible region:$1$. At $(0, 2): F = 4(0) + 6(2) = 0 + 12 = 12$$2$. At $(3, 0): F = 4(3) + 6(0) = 12 + 0 = 12$$3$. At $(6, 0): F = 4(6) + 6(0) = 24 + 0 = 24$$4$. At $(6, 8): F = 4(6) + 6(8) = 24 + 48 = 72$$5$. At $(0, 5): F = 4(0) + 6(5) = 0 + 30 = 30$Comparing these values,the maximum value of $F$ is $72$ and the minimum value of $F$ is $12$.Therefore,$	ext{Maximum of } F - 	ext{Minimum of } F = 72 - 12 = 60$.

Corner points of the feasible region for an $\operatorname{LPP}$ are $(0,2), (3,0), (6,0), (6,8)$ and $(0,5)$. Let $F = 4x + 6y$ be the objective function. Find the value of $\text{Maximum of } F - \text{Minimum of } F$.

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