Construct $\Delta XYZ$ in which $\angle Y = 45^{\circ}$,$\angle Z = 60^{\circ}$ and $XY + YZ + ZX = 10 \, cm$. Write the steps of construction.

(N/A) Steps of construction:
$1$. Draw a line segment $PQ = 10 \, cm$ (where $PQ = XY + YZ + ZX$).
$2$. Construct an angle $\angle P = 45^{\circ}$ at point $P$ and $\angle Q = 60^{\circ}$ at point $Q$.
$3$. Bisect $\angle P$ and $\angle Q$. Let the bisectors intersect at point $X$.
$4$. Draw the perpendicular bisector of $PX$ and $QX$. Let these intersect $PQ$ at $Y$ and $Z$ respectively.
$5$. Join $XY$ and $XZ$. Thus,$\Delta XYZ$ is the required triangle.