Consider the vectors $\vec{a}=3 \hat{i}+5 \hat{j}+2 \hat{k}$,$\vec{b}=2 \hat{i}-3 \hat{j}-5 \hat{k}$ and $\vec{c}=-5 \hat{i}-2 \hat{j}+3 \hat{k}$. If $l, m$ and $n$ are the lengths of the projections of $\vec{a}$ on $\vec{b}$,$\vec{b}$ on $\vec{c}$ and $\vec{c}$ on $\vec{a}$ respectively,then:

  • A
    $l+m-n=0$
  • B
    $l=m=n$
  • C
    $l-m+n=0$
  • D
    $m+n-l=0$

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