Consider the situation given in the figure. T | vedclass

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(D) The motional electromotive force (emf) induced in a conductor moving in a magnetic field is given by $e = \int (\vec{v} 	imes \vec{B}) \cdot d\ve

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remain same

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(D) The motional electromotive force (emf) induced in a conductor moving in a magnetic field is given by $e = \int (\vec{v} 	imes \vec{B}) \cdot d\vec{l}$.For a conductor moving with velocity $v$ perpendicular to a uniform magnetic field $B$,the induced emf is $e = B v L_{eff}$,where $L_{eff}$ is the effective length of the conductor perpendicular to the velocity vector.The effective length $L_{eff}$ is the straight-line distance between the two ends of the wire that are in contact with the rails.When the straight wire $AB$ is replaced by a semicircular wire with the same endpoints $A$ and $B$,the effective length $L_{eff}$ (the distance between $A$ and $B$) remains the same.Since the induced emf $e = B v L_{eff}$ depends only on the distance between the contact points on the rails,the emf remains unchanged.Assuming the resistance $R$ of the circuit remains constant,the induced current $i = e/R$ will also remain the same.

Consider the situation given in the figure. The wire $AB$ is slid on the fixed rails with a constant velocity $v$. If the wire $AB$ is replaced by a semicircular wire of the same length,the magnitude of the induced current will:

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