Consider the parabola $P : y^2 = 4x$ and the ellipse $E : \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$. Let the line segment joining the points of intersection of $P$ and $E$ be their common latus rectum. If the eccentricity of $E$ is $e$,then $e^2 + 2\sqrt{2}$ is equal to . . . . . .

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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