Consider the metal complexes [Ni(en)_3]^{2+} | vedclass

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Question

$(A)$ For the complex $[Ni(en)_3]^{2+}$ $(A)$: $Ni^{2+}$ has a $d^8$ configuration. Since it is an octahedral complex with a strong field ligand $(en)

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$2, 2, 2$ and $(A) > (C) > (B)$

Vedclass · Answer

$(A)$ For the complex $[Ni(en)_3]^{2+}$ $(A)$: $Ni^{2+}$ has a $d^8$ configuration. Since it is an octahedral complex with a strong field ligand $(en)$, it has $2$ unpaired electrons.
For the complex $[NiCl_4]^{2-}$ $(B)$: $Ni^{2+}$ has a $d^8$ configuration. It is a tetrahedral complex with a weak field ligand $(Cl^-)$, resulting in $2$ unpaired electrons.
For the complex $[Ni(NH_3)_6]^{2+}$ $(C)$: $Ni^{2+}$ has a $d^8$ configuration. It is an octahedral complex with a moderate field ligand $(NH_3)$, resulting in $2$ unpaired electrons.
The absorption frequency is directly proportional to the crystal field splitting energy $(\Delta)$. The spectrochemical series order for the ligands is $(en) > (NH_3) > (Cl^-)$.
Therefore, the order of frequency of absorption is $(A) > (C) > (B)$.

Consider the metal complexes $[Ni(en)_3]^{2+}$ $(A)$, $[NiCl_4]^{2-}$ $(B)$ and $[Ni(NH_3)_6]^{2+}$ $(C)$. Choose the $\text{CORRECT}$ option by considering the number of unpaired electrons present in $(A)$, $(B)$ and $(C)$ respectively and the order of frequency of absorption.

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