Consider the hydrated ions of Ti^{2+}, V^{2+} | vedclass

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Question

$T{i^{ + 2}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^2}$

unpaired electron $=\,2$

spin only magnetic moment $(\mu )\, = \,\sqrt {

Vedclass · Accepted Answer

$Sc^{3+} < Ti^{3+} < Ti^2 < V^{2+}$

Vedclass · Answer

$T{i^{ + 2}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^2}$

unpaired electron $=\,2$

spin only magnetic moment $(\mu )\, = \,\sqrt {2(2 + 2)} \, = \,\sqrt 8 \,B.M$

$T{i^{ + 3}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^1}$

unpaired electron $=\,1$

$(\mu )\, = \,\sqrt {1(1 + 2)} \, = \,\sqrt 3 \,B.M$

${V^{ + 2}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^3}$

$(\mu )\, = \,\sqrt {3(3 + 2)} \, = \,\sqrt {15} \,B.M$

$S{c^{ + 3}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}$

$(\mu )\, =0$

Consider the hydrated ions of $Ti^{2+}, V^{2+}, Ti^{3+}$ and $Sc^{3+}$. The correct order of their spin-only magnetic moments is

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