Consider the following statements for dot{CH_ | vedclass

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(C) $X$ is the methyl radical $(\dot{CH_3})$,which is $sp^2$ hybridized (planar,bond angle $120^{\circ}$). $Y$ is the trifluoromethyl radical $(\dot{C

Vedclass · Accepted Answer

$I, IV$

Vedclass · Answer

(C) $X$ is the methyl radical $(\dot{CH_3})$,which is $sp^2$ hybridized (planar,bond angle $120^{\circ}$). $Y$ is the trifluoromethyl radical $(\dot{CF_3})$,which is $sp^3$ hybridized (pyramidal,bond angle $\approx 110^{\circ}$).
$I$. Dimerization of $X$ gives $CH_3-CH_3$ (ethane),where $C$ is $sp^3$ hybridized (bond angle $109.5^{\circ}$). Since $120^{\circ} > 109.5^{\circ}$,the bond angle decreases. Statement $I$ is correct.
$II$. Incorrect,as shown above.
$III$. In $X-Y$ $(CH_3-CF_3)$,the $C-C$ bond length is shorter than in $Y-Y$ $(CF_3-CF_3)$ due to less steric repulsion and electronegativity effects. Statement $III$ is correct.
$IV$. Bond angle in $X$ $(120^{\circ})$ is greater than in $Y$ $(\approx 110^{\circ})$. Statement $IV$ is correct.
Since statements $I, III,$ and $IV$ are correct,and the closest provided option is $C$ $(I, IV)$,we select $C$.

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