To obtain 3-methylbutan-2-ol from acetaldehyd | vedclass

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(D) The reaction of acetaldehyde $(CH_3CHO)$ with a Grignard reagent $(RMgBr)$ followed by acid hydrolysis $(H_3O^+)$ yields a secondary alcohol.To ob

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$(CH_3)_2CHMgBr$

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(D) The reaction of acetaldehyde $(CH_3CHO)$ with a Grignard reagent $(RMgBr)$ followed by acid hydrolysis $(H_3O^+)$ yields a secondary alcohol.To obtain $3-$methylbutan$-2-$ol $(CH_3-CH(OH)-CH(CH_3)_2)$,the Grignard reagent must provide the isopropyl group $(CH(CH_3)_2)$.The reaction is as follows:$CH_3-CH=O + (CH_3)_2CHMgBr \rightarrow CH_3-CH(OMgBr)-CH(CH_3)_2$$CH_3-CH(OMgBr)-CH(CH_3)_2 + H_2O/H^+ \rightarrow CH_3-CH(OH)-CH(CH_3)_2 + Mg(OH)Br$Thus,the required Grignard reagent is isopropylmagnesium bromide,which is $(CH_3)_2CHMgBr$.

To obtain $3-$methylbutan$-2-$ol from acetaldehyde,the Grignard's reagent used is

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