Consider the following reactions:X(aq.) xrigh | vedclass

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(B) The reaction of $Cu^{2+}$ ions with potassium ferrocyanide $(K_4[Fe(CN)_6])$ produces a chocolate brown precipitate of copper$(II)$ hexacyanoferra

Vedclass · Accepted Answer

$CuCl_2$

Vedclass · Answer

(B) The reaction of $Cu^{2+}$ ions with potassium ferrocyanide $(K_4[Fe(CN)_6])$ produces a chocolate brown precipitate of copper$(II)$ hexacyanoferrate$(II)$,$Cu_2[Fe(CN)_6]$.The reaction is: $2CuCl_2(aq.) + K_4[Fe(CN)_6](aq.) \rightarrow Cu_2[Fe(CN)_6](s) + 4KCl(aq.)$The reaction of $Cl^-$ ions with silver nitrate $(AgNO_3)$ produces a white precipitate of silver chloride $(AgCl)$,which is insoluble in dilute $HNO_3$.The reaction is: $CuCl_2(aq.) + 2AgNO_3(aq.) \rightarrow 2AgCl(s) + Cu(NO_3)_2(aq.)$Therefore,$X$ is $CuCl_2$.

Consider the following reactions:
$X(aq.) \xrightarrow{K_4[Fe(CN)_6]}$ Chocolate brown ppt.
$X(aq.) \xrightarrow{AgNO_3}$ White ppt. (insoluble in dil. $HNO_3$)
Then $X$ will be:

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Consider the following reactions:$X(aq.) \xrightarrow{K_4[Fe(CN)_6]}$ Chocolate brown ppt.$X(aq.) \xrightarrow{AgNO_3}$ White ppt. (insoluble in dil. $HNO_3$)Then $X$ will be: