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(D) When $S_1$ is closed,the capacitor $C$ charges to a potential $V$. The energy stored in the capacitor is $U_E = \frac{1}{2} CV^2$.When $S_1$ is op

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At any time $t > 0$,the instantaneous current in the circuit may be $V \sqrt{\frac{C}{L}}$.

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(D) When $S_1$ is closed,the capacitor $C$ charges to a potential $V$. The energy stored in the capacitor is $U_E = \frac{1}{2} CV^2$.When $S_1$ is opened and $S_2$ is closed,the capacitor discharges through the inductor $L$,forming an $LC$ oscillation circuit.At $t = 0$ (the moment $S_2$ is closed),the energy is entirely electric (stored in the capacitor).As the capacitor discharges,the energy oscillates between the electric field of the capacitor and the magnetic field of the inductor.By the law of conservation of energy,the maximum electric energy equals the maximum magnetic energy:$\frac{1}{2} CV^2 = \frac{1}{2} LI_{max}^2$$I_{max}^2 = \frac{C}{L} V^2$$I_{max} = V \sqrt{\frac{C}{L}}$Thus,the instantaneous current in the circuit can reach a maximum value of $V \sqrt{\frac{C}{L}}$.

Consider the following circuit. By keeping $S_1$ closed,the capacitor is fully charged and then $S_1$ is opened and $S_2$ is closed,then

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