Consider the following carbocations:I. C_6H_5 | vedclass

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(A) The stability of carbocations is determined by resonance,hyperconjugation,and inductive effects.$I$ $(C_6H_5CH_2^+)$ is a benzylic carbocation,whi

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$I > III > IV > II > V$

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(A) The stability of carbocations is determined by resonance,hyperconjugation,and inductive effects.$I$ $(C_6H_5CH_2^+)$ is a benzylic carbocation,which is highly stabilized by resonance with the phenyl ring.$III$ $(CH_3-CH^+(CH_3))$ is a secondary $(2^{\circ})$ carbocation,stabilized by hyperconjugation and inductive effects of two methyl groups.$IV$ $(CH_3-CH_2^+)$ is a primary $(1^{\circ})$ carbocation,stabilized by hyperconjugation and inductive effects of one methyl group.$II$ $(CH_2=CH^+)$ is a vinylic carbocation,and $V$ $(HC \equiv C^+)$ is an acetylenic carbocation. Both have the positive charge on an $sp^2$ and $sp$ hybridized carbon,respectively. Higher $s$-character increases electronegativity,making the positive charge less stable.Since $sp$ hybridization ($50\% \ s$-character) is more electronegative than $sp^2$ hybridization ($33.3\% \ s$-character),$V$ is less stable than $II$.Thus,the decreasing order of stability is $I > III > IV > II > V$.

Consider the following carbocations:
$I. C_6H_5CH_2^+$
$II. CH_2=CH^+$
$III. CH_3-CH^+(CH_3)$
$IV. CH_3-CH_2^+$
$V. HC \equiv C^+$
Arrange the above carbocations in the order of decreasing stability.

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Consider the following carbocations:$I. C_6H_5CH_2^+$$II. CH_2=CH^+$$III. CH_3-CH^+(CH_3)$$IV. CH_3-CH_2^+$$V. HC \equiv C^+$Arrange the above carbocations in the order of decreasing stability.