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(C) Given: Radius $R = 5 \ m$,tangential velocity $v = 2 \ ms^{-1}$.For uniform circular motion,the angular velocity $\omega$ is given by $\omega = \f

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$10 \pi \ s$ and $0.8 \ ms^{-2}$

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(C) Given: Radius $R = 5 \ m$,tangential velocity $v = 2 \ ms^{-1}$.For uniform circular motion,the angular velocity $\omega$ is given by $\omega = \frac{v}{R} = \frac{2}{5} = 0.4 \ rad \ s^{-1}$.The time period $T$ for one revolution is $T = \frac{2 \pi}{\omega} = \frac{2 \pi}{0.4} = 5 \pi \ s$.The time taken to complete $2$ revolutions is $t = 2 	imes T = 2 	imes 5 \pi = 10 \pi \ s$.The magnitude of centripetal acceleration $a_c$ is $a_c = \frac{v^2}{R} = \frac{2^2}{5} = \frac{4}{5} = 0.8 \ ms^{-2}$.Thus,the time taken is $10 \pi \ s$ and the acceleration is $0.8 \ ms^{-2}$.

Consider an object making uniform motion around a circle of radius $5 \ m$ with tangential velocity $2 \ ms^{-1}$. The time it takes to complete $2$ revolutions and the magnitude of acceleration respectively are

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