Consider a square of side $2 \ cm$. It is cut from one of its corners as shown in the adjacent figure. The maximum value of the sum of the perimeters of the two plane figures thus formed is

  • A
    $2\sqrt{2} + 8$
  • B
    $12$
  • C
    $8$
  • D
    $4\sqrt{2} + 8$

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