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(A) The solenoid is connected to a $DC$ source with a constant $emf$ $(V)$.The current in the solenoid is given by $I = V/R$,where $R$ is the resistan

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remain same

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(A) The solenoid is connected to a $DC$ source with a constant $emf$ $(V)$.The current in the solenoid is given by $I = V/R$,where $R$ is the resistance of the solenoid wire.When the iron core is pulled out,the self-inductance $(L)$ of the solenoid changes,but the resistance $(R)$ of the wire remains constant.Since the $DC$ source provides a constant $emf$ and the resistance of the circuit does not change,the steady-state current $I$ remains unchanged.Therefore,the current will remain the same.

Consider a solenoid carrying current supplied by a $DC$ source with a constant $emf$ containing an iron core inside it. When the core is pulled out of the solenoid,the change in current will:

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