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(C) In a pure inductive circuit,the current $I$ lags behind the voltage $V$ by a phase angle of $\phi = 90^{\circ}$ (or $\pi/2$ radians).The average p

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$P = 0$

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(C) In a pure inductive circuit,the current $I$ lags behind the voltage $V$ by a phase angle of $\phi = 90^{\circ}$ (or $\pi/2$ radians).The average power consumed in an $A$.$C$. circuit is given by the formula $P = V_{rms} I_{rms} \cos \phi$.Substituting the phase angle $\phi = 90^{\circ}$ into the formula,we get $\cos 90^{\circ} = 0$.Therefore,$P = V_{rms} I_{rms} 	imes 0 = 0$.Thus,a pure inductor consumes no average power.

Consider a pure inductive $A$.$C$. circuit as shown in the figure. If the average power consumed is $P$,then

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