$A$ $100 \mu F$ capacitor is connected to a $100 \text{ V}$, $50 \text{ Hz}$ $AC$ supply. The rms value of the current is (in $\text{ A}$)

Explain the dissipation of electrical energy when an alternating current passes through a resistor.

An alternating voltage $E = 100 \sqrt{2} \sin(50 t)$ is connected to a $2 \mu F$ capacitor through an a.c. ammeter. The ammeter reading will be (in $\text{ mA}$)

Let $f = 50\, Hz$ and $C = 100\, \mu F$ in an $AC$ circuit containing a capacitor only. If the peak value of the current in the circuit is $1.57\, A$,the expression for the instantaneous voltage across the capacitor will be (assuming current is $I = I_m \sin(\omega t)$):

In the case of an inductor,

$A$ capacitor of capacitance $150.0\,\mu F$ is connected to an alternating source of $emf$ given by $E = 36 \sin(120 \pi t) \, V$. The maximum value of current in the circuit is approximately equal to $...... \, A$.