Consider a physical quantity $Z$ expressed as $Z = \frac{A B^{1/2}}{C^2}$. If the relative error in the magnitudes of $A, B,$ and $C$ is $1\%$,then the relative error in $Z$ will be: (in $\%$)

If the error in the measurement of the surface area of a sphere is $1.2 \%$,then the error in the determination of the volume of the sphere is (in $\%$)

The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are:

If the maximum percentage error in the measurement of distance $(h)$ and time $(t)$ are '$e_1$' and '$e_2$' respectively,the percentage error in the measurement of acceleration of gravity $(g)$ is [use $h=\frac{1}{2} gt^2$].

Find the relative error in $Z$,if $Z = \frac{A^{4} B^{1/3}}{C D^{3/2}}$.

In the expression for time period $T$ of a simple pendulum $T = 2 \pi \sqrt{\frac{l}{g}}$,if the percentage error in time period $T$ and length $l$ are $2 \%$ and $2 \%$ respectively,then the percentage error in acceleration due to gravity $g$ is equal to ......... $\%$