Consider a galvanometer shunted with $5\, \Omega$ resistance and $2\, \%$ of the total current passes through it. What is the resistance of the given galvanometer? (In $\Omega$)

$A$ galvanometer having a coil resistance of $60\,\Omega$ shows full-scale deflection when a current of $1.0\,A$ passes through it. It can be converted into an ammeter to read currents up to $5.0\,A$ by:

$A$ galvanometer of resistance $25\,\Omega$ gives full-scale deflection for a current of $10\,mA$. It is to be converted into a voltmeter of range $100\,V$ by connecting a resistance $R$ in series with the galvanometer. The value of resistance $R$ in $\Omega$ is:

$A$ galvanometer having internal resistance $10 \Omega$ requires $0.01 \ A$ for a full scale deflection. To convert this galvanometer to a voltmeter of full-scale deflection at $120 \ V$,we need to connect a resistance of

$A$ galvanometer of resistance $G$ is shunted by a resistance $S$. To keep the main current in the circuit unchanged,the resistance to be put in series with the galvanometer is

If only $2\%$ of the main current is to be passed through a galvanometer of resistance $G$,then the resistance of the shunt will be