$A$ galvanometer having internal resistance $10 \Omega$ requires $0.01 \ A$ for a full scale deflection. To convert this galvanometer to a voltmeter of full-scale deflection at $120 \ V$,we need to connect a resistance of

  • A
    $11990 \ \Omega$ in series
  • B
    $11990 \ \Omega$ in parallel
  • C
    $12010 \ \Omega$ in series
  • D
    $12010 \ \Omega$ in parallel

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Similar Questions

$A$ galvanometer having coil resistance $10 \ \Omega$ shows a full scale deflection for a current of $3 \ mA$. For it to measure a current of $8 \ A$,the value of the shunt should be:

$A$ galvanometer having a resistance of $20\,\Omega$ and $30\,divisions$ on both sides has a figure of merit of $0.005\,A/division$. The resistance that should be connected in series so that it can be used as a voltmeter up to $15\,V$ is ........... $\Omega$.

Match the terms given in List-$I$ with suitable options provided in List-$II$ regarding the experiment to calculate the resistance and figure of merit of a galvanometer using the half-deflection method:
List-$I$ List-$II$
$A$. Figure of merit $(k)$ $P$. in series
$B$. Current sensitivity $(SI)$ $Q$. to get power loss minimized
$C$. Deflection is made half by using low resistance $R$. in shunt/parallel
$D$. High resistance box $S$. current per unit deflection
$T$. deflection per unit current

The ratios of the voltage sensitivities,resistances and areas of the coils of two moving coil galvanometers $A$ and $B$ are $4:3$,$3:4$ and $1:2$ respectively. If the number of turns of the coil of galvanometer $A$ is $200$,then the number of turns of the coil of galvanometer $B$ is (All other quantities remain same in both the cases)

An ammeter, suspected to give inaccurate reading, is connected in series with a silver voltameter. The ammeter indicates $0.54\, A$. A steady current passed for one hour deposits $2.0124\, g$ of silver. If the $E.C.E.$ of silver is $1.118 \times 10^{-3}\, g\, C^{-1}$, then the error in ammeter reading is ................ $A$.

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