Consider a drop of rain water having mass 1, | vedclass

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Question

$\begin{gathered}
  \,\,\,Here,\,m = 1\,g = {10^{ - 3}}kg,h = 1\,km \hfill \
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,

Vedclass · Accepted Answer

$10\;J,\;\; - 8.75\;J\;$

Vedclass · Answer

$\begin{gathered}
  \,\,\,Here,\,m = 1\,g = {10^{ - 3}}kg,h = 1\,km \hfill \
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 100\,m, \hfill \
  v = 50\,m{s^{ - 1}},g = 10m{s^{ - 2}} \hfill \
  \left( i ight)\,The\,work\,done\,by\,the\,gravitational\, \hfill \
  force \hfill \
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = mgh = {10^{ - 3}} 	imes 10 	imes 1000 = 10\,J \hfill \ 
\end{gathered} $

$\begin{gathered}
  \left( {ii} ight)The\,total\,work\,done\,by\,gravitational\, \hfill \
  force\,and\,the\,resistive\,force\,of\,air\,is\, \hfill \
  equal\,to\,change\,in\,kinetic\,energy\,of\, \hfill \
  rain\,drop. \hfill \
  	herefore \,{W_g} + {W_r} = \frac{1}{2}m{v^2} - 0 \hfill \
  10 + {W_r} = \frac{1}{2} 	imes {10^{ - 3}} 	imes 50 	imes 50\,or\, \hfill \
  {W_r} =  - 8.75\,J \hfill \ 
\end{gathered} $

Consider a drop of rain water having mass $1\, g$ falling from a height of $1\, km.$ It hits the ground with a speed of $50\, m s^{-1}$. Take $g$ constant with a value $10 \, m s^{-1}$. The work done by the $(i)$ gravitational force and the $(ii)$ resistive force of air is

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