Compounds with high heat of formation are less stable because

  • A
    High temperature is required to synthesise them
  • B
    Molecules of such compounds are distorted
  • C
    It is difficult to synthesis them
  • D
    Energy rich state leads to instability

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The heat of neutralisation of one equivalent of an acid by one equivalent of a base is minimum when:

If $C_{(s)} + O_{2(g)} \rightarrow CO_{2(g)}$,$\Delta H = -X$,and $CO_{(g)} + \frac{1}{2} O_{2(g)} \rightarrow CO_{2(g)}$,$\Delta H = -Y$,calculate $\Delta_f H$ for $CO_{(g)}$ formation.

The heat of solution of anhydrous $CuSO_4$ and $CuSO_4 \cdot 5 H_2 O$ are $-70 \ kJ \ mol^{-1}$ and $+12 \ kJ \ mol^{-1}$ respectively. The heat of hydration of $CuSO_4$ to $CuSO_4 \cdot 5 H_2 O$ is $-x \ kJ$. The value of $x$ is:

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