Compound(s) that on hydrogenation produce(s) | vedclass

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(D) Hydrogenation of the given compounds results in the following products:$(A)$ $CH_3-CH=CH-CH(Br)CH_3 \xrightarrow{H_2/Pt} CH_3-CH_2-CH_2-CH(Br)CH_3

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$(B, D)$

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(D) Hydrogenation of the given compounds results in the following products:$(A)$ $CH_3-CH=CH-CH(Br)CH_3 \xrightarrow{H_2/Pt} CH_3-CH_2-CH_2-CH(Br)CH_3$. The product has a chiral center and is optically active.$(B)$ $H_2C=CH-CH(Br)CH_2CH_3 \xrightarrow{H_2/Pt} CH_3-CH_2-CH(Br)CH_2CH_3$. The product is $3$-bromopentane,which has a plane of symmetry and is optically inactive.$(C)$ $H_2C=C(CH_3)-CH(Br)CH_3 \xrightarrow{H_2/Pt} CH_3-CH(CH_3)-CH(Br)CH_3$. The product has two chiral centers and is optically active.$(D)$ $H_2C=CH-C(Br)(H)CH_2CH_3 \xrightarrow{H_2/Pt} CH_3-CH_2-CH(Br)CH_2CH_3$. The product is $3$-bromopentane,which is optically inactive.Thus,compounds $(B)$ and $(D)$ produce optically inactive compounds upon hydrogenation.

Compound$(s)$ that on hydrogenation produce$(s)$ optically inactive compound$(s)$ is (are)

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