Which of the following reactions does not inv | vedclass

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Question

(A) In the reaction $CH_3-CH=CH_2 \xrightarrow{HBr, H_2O_2} CH_3-CH_2-CH_2Br$,the mechanism involves a free radical intermediate (peroxide effect or K

Vedclass · Accepted Answer

$CH_3-CH=CH_2 \xrightarrow{HBr, H_2O_2} CH_3-CH_2-CH_2Br$

Vedclass · Answer

(A) In the reaction $CH_3-CH=CH_2 \xrightarrow{HBr, H_2O_2} CH_3-CH_2-CH_2Br$,the mechanism involves a free radical intermediate (peroxide effect or Kharasch effect),not a carbocation.In $CH_3-CH=CH_2 \xrightarrow{HCl} CH_3-CHCl-CH_3$,the mechanism involves the formation of a secondary carbocation intermediate.In $(CH_3)_3C-OH \xrightarrow{H^+, \Delta} (CH_3)_2C=CH_2 + H_2O$,the dehydration of alcohol involves the formation of a tertiary carbocation intermediate.In $C_6H_6 + CH_3Cl \xrightarrow{AlCl_3} C_6H_5-CH_3 + HCl$,the Friedel-Crafts alkylation involves the formation of an electrophilic carbocation $(CH_3^+)$ intermediate.Therefore,the reaction that does not involve a carbocation is the anti-Markovnikov addition of $HBr$ in the presence of peroxide.

Which of the following reactions does not involve a carbocation as an intermediate?

Similar Questions

The major product in the following reaction is

The name of the product obtained by the addition of $HI$ to propene in the presence of a peroxide catalyst is:

What will be the product of the reaction: $CH_3-CH=C(CH_3)_2 + HCl \to$ ?

Assertion : $1$-Butene on reaction with $HBr$ in the presence of a peroxide produces $1$-bromobutane.
Reason : It involves the formation of a primary radical.

Which of the following is the most stable alkene?

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