Compound A on borax bead test in reducing fla | vedclass

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(C) $1$. The borax bead test for $Cr^{3+}$ in a reducing flame produces a green-colored bead due to the formation of $Cr_2O_3$. $2$. When $Cr^{3+}$ co

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$Cr^{3+}$

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(C) $1$. The borax bead test for $Cr^{3+}$ in a reducing flame produces a green-colored bead due to the formation of $Cr_2O_3$. $2$. When $Cr^{3+}$ compounds are treated with $H_2O_2$ in an alkaline medium,they are oxidized to chromate ions $(CrO_4^{2-})$. $3$. The chromate ions react with lead$(II)$ acetate $(Pb(OAc)_2)$ to form a yellow precipitate of lead chromate $(PbCrO_4)$. $4$. Therefore,the metal ion present in compound $A$ is $Cr^{3+}$.

Compound $A$ on borax bead test in reducing flame gives green colour bead. Compound $A$ on treatment with $H_2O_2$ followed by treatment with $Pb(OAc)_2$ gives yellow ppt. The metal ion in the compound $A$ is :

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