Complete removal of both the axial ligands (a | vedclass

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(B) In an octahedral complex,the ligands are present along the $x, y,$ and $z$ axes. When the two ligands along the $z-$ axis are removed,the complex

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(B) In an octahedral complex,the ligands are present along the $x, y,$ and $z$ axes. When the two ligands along the $z-$ axis are removed,the complex becomes square planar. The ligands now exert repulsion only along the $x$ and $y$ axes. Consequently,the orbitals with components along the $x$ and $y$ axes ($d_{x^2-y^2}$ and $d_{xy}$) will experience higher repulsion and thus have higher energy. The $d_{z^2}$ orbital,having no ligand interaction along the $z-$ axis,will decrease significantly in energy. The $d_{xz}$ and $d_{yz}$ orbitals will also decrease in energy but remain higher than $d_{z^2}$ due to their interaction with the $x$ and $y$ ligands. The correct splitting pattern for a square planar complex is $d_{x^2-y^2} > d_{xy} > d_{z^2} > d_{xz}, d_{yz}$,which corresponds to the pattern shown in image $821-b1769$.

Complete removal of both the axial ligands (along the $z-$ axis) from an octahedral complex leads to which of the following splitting patterns? (relative orbital energies not on scale)

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