Compare the rate of dehydration of (i),(ii) a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The rate of dehydration of alcohols depends on the stability of the carbocation intermediate formed after the loss of water. $(i)$ forms a carboca

Vedclass · Accepted Answer

$(i) > (ii) > (iii)$

Vedclass · Answer

(B) The rate of dehydration of alcohols depends on the stability of the carbocation intermediate formed after the loss of water. $(i)$ forms a carbocation that is resonance-stabilized by the adjacent double bond and the benzene ring. $(ii)$ forms a secondary benzylic carbocation,which is stabilized by the benzene ring. $(iii)$ forms a vinylic carbocation,which is highly unstable. Comparing the stability: $(i)$ (allylic and benzylic resonance) > $(ii)$ (benzylic) > $(iii)$ (vinylic). Therefore,the rate of dehydration follows the order $(i) > (ii) > (iii)$.

Compare the rate of dehydration of $(i)$,$(ii)$ and $(iii)$ by conc. $H_2SO_4$.

Similar Questions

In the following sequence of reaction,$Z$ $\xrightarrow{PCl_5} X$ $\xrightarrow[\Delta]{\text{Alc. KOH}} Y$ $\xrightarrow{H_2O/H^{+}} Z$ (Major),$Z$ is:

What is obtained when ethyl alcohol is heated with red phosphorus and $HI$?

Describe the reactions of alcohols with $(a)$ $HX$ and Lucas test,$(b)$ $PX_3$,and $(c)$ dehydration reactions.

An alcohol on oxidation is found to give $CH_3COOH$ and $CH_3CH_2COOH$. The structure of the alcohol is

Ethyl alcohol on heating with conc. $H_2SO_4$ gives

Vedclass Test Series

Exam Paper Generator

Online Exam Module