In the following sequence of reaction,Z xrigh | vedclass

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(B) The correct answer is $(b)$.$1.$ $CH_3-CH(OH)-CH_3 (Z) \xrightarrow{PCl_5} CH_3-CHCl-CH_3 (X)$$2.$ $CH_3-CHCl-CH_3 (X) \xrightarrow{	ext{Alc. KOH

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$CH_3-CH(OH)-CH_3$

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(B) The correct answer is $(b)$.$1.$ $CH_3-CH(OH)-CH_3 (Z) \xrightarrow{PCl_5} CH_3-CHCl-CH_3 (X)$$2.$ $CH_3-CHCl-CH_3 (X) \xrightarrow{	ext{Alc. KOH}, \Delta} CH_3-CH=CH_2 (Y)$$3.$ $CH_3-CH=CH_2 (Y) \xrightarrow{H_2O/H^{+}} CH_3-CH(OH)-CH_3 (Z)$The hydration of propene follows Markovnikov's rule,where the $-OH$ group adds to the more substituted carbon,regenerating Propan-$2$-ol. Thus,$Z$ is Propan-$2$-ol.

In the following sequence of reaction,$Z$ $\xrightarrow{PCl_5} X$ $\xrightarrow[\Delta]{\text{Alc. KOH}} Y$ $\xrightarrow{H_2O/H^{+}} Z$ (Major),$Z$ is:

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