Chlorine has two naturally occurring isotopes | vedclass

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(B) Let the natural abundance of ${}^{35}Cl$ be $x$ and that of ${}^{37}Cl$ be $y$.The average atomic mass is given by the formula: $M_{av} = \frac{M_

Vedclass · Accepted Answer

$3$

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(B) Let the natural abundance of ${}^{35}Cl$ be $x$ and that of ${}^{37}Cl$ be $y$.The average atomic mass is given by the formula: $M_{av} = \frac{M_{1}x + M_{2}y}{x + y}$.Substituting the given values: $35.45 = \frac{35x + 37y}{x + y}$.$35.45(x + y) = 35x + 37y$.$35.45x + 35.45y = 35x + 37y$.$0.45x = 1.55y$.$\frac{x}{y} = \frac{1.55}{0.45} = \frac{155}{45} \approx 3.44$.The ratio is closest to $3: 1$.

Chlorine has two naturally occurring isotopes,${}^{35}Cl$ and ${}^{37}Cl$. If the atomic mass of $Cl$ is $35.45$,the ratio of natural abundance of ${}^{35}Cl$ and ${}^{37}Cl$ is closest to (in $: 1$)

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