The chemical formula of rust is:
- A$FeO$
- B$Fe_3O_4$
- C$Fe_2O_3 \cdot xH_2O$
- D$FeO \cdot xH_2O$
Explore More
Similar Questions
What is the percentage of $H_2O$ in $Fe(CNS)_3 \cdot 3H_2O$?
Medium
View SolutionWhat is the percentage composition of $C$ in methanoic anhydride?
Medium
View SolutionWhen $0.01 \ mol$ of an organic compound containing $60 \%$ carbon was burnt completely,$4.4 \ g$ of $CO_2$ was produced. The molar mass of the compound is $......... \ g \ mol^{-1}$ (Nearest integer).
DifficultJEE MAIN 2023
View SolutionAn organic compound has $42.1 \%$ carbon,$6.4 \%$ hydrogen and the remainder is oxygen. If its molecular weight is $342$,then its molecular formula is:
DifficultJEE MAIN 2024
View Solution$A$ transition metal $M$ forms a volatile chloride which has a vapour density of $94.8$. If it contains $74.75\%$ of chlorine,the formula of the metal chloride will be:
DifficultAIEEE 2012
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo