Calculate the solubility of $A_{2}X_{3}$ in pure water,assuming that neither kind of ion reacts with water. The solubility product of $A_{2}X_{3}$,$K_{sp} = 1.1 \times 10^{-23}$.

Solubility product of $AgBr$ is $4.9 \times 10^{-13}$. What is its solubility?

At $20 \, ^\circ C$,the $Ag^+$ ion concentration in a saturated solution of $Ag_2CrO_4$ is $1.5 \times 10^{-4} \, mol/L$. At $20 \, ^\circ C$,the solubility product of $Ag_2CrO_4$ would be:

The solubility product $(K_{sp})$ of the following compounds are given at $25\,\text{°C}$:

Compound	$K_{sp}$
$AgCl$	$1.1 \times 10^{-10}$
$AgI$	$1.0 \times 10^{-16}$
$PbCrO_4$	$4.0 \times 10^{-14}$
$Ag_2CO_3$	$8.0 \times 10^{-12}$

The most soluble and least soluble compounds are respectively:

For a sparingly soluble strong electrolyte $AgIO_3$ (molar mass = $283 \, g/mol$),the equilibrium in a saturated solution is given by $AgIO_3(s) \rightleftharpoons Ag^+(aq) + IO_3^-(aq)$. If the solubility product constant $K_{sp}$ of $AgIO_3$ at a given temperature is $1.0 \times 10^{-8}$,how many grams of $AgIO_3$ are contained in $100 \, mL$ of its saturated solution?

If the solubility of lithium sodium hexafluoroaluminate $Li_3Na_3(AlF_6)_2$ is $S \ mol/L$,then its solubility product $K_{sp}$ is equal to?