If the solubility of lithium sodium hexafluor | vedclass

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Question

(D) The dissociation of the salt is given by: $Li_3Na_3(AlF_6)_2 \rightleftharpoons 3Li^+ + 3Na^+ + 2[AlF_6]^{3-}$.Let the solubility be $S \ mol/L$.T

Vedclass · Accepted Answer

$2916 \ S^8$

Vedclass · Answer

(D) The dissociation of the salt is given by: $Li_3Na_3(AlF_6)_2 ightleftharpoons 3Li^+ + 3Na^+ + 2[AlF_6]^{3-}$.Let the solubility be $S \ mol/L$.The concentrations of the ions are: $[Li^+] = 3S$,$[Na^+] = 3S$,and $[[AlF_6]^{3-}] = 2S$.The solubility product expression is: $K_{sp} = [Li^+]^3 	imes [Na^+]^3 	imes [[AlF_6]^{3-}]^2$.Substituting the values: $K_{sp} = (3S)^3 	imes (3S)^3 	imes (2S)^2$.$K_{sp} = (27S^3) 	imes (27S^3) 	imes (4S^2)$.$K_{sp} = 2916 \ S^8$.

If the solubility of lithium sodium hexafluoroaluminate $Li_3Na_3(AlF_6)_2$ is $S \ mol/L$,then its solubility product $K_{sp}$ is equal to?

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