Calculate the rate constant of a first-order | vedclass

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Question

(D) For a first-order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log_{10} \frac{[A]_0}{[A]_t}$.If the concentration

Vedclass · Accepted Answer

$7.67 	imes 10^{-2} \ min^{-1}$

Vedclass · Answer

(D) For a first-order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log_{10} \frac{[A]_0}{[A]_t}$.If the concentration decreases by $90 \%$,then the remaining concentration $[A]_t$ is $10 \%$ of the initial concentration $[A]_0$.So,$[A]_t = 0.1 [A]_0$ or $\frac{[A]_0}{[A]_t} = 10$.Given $t = 30 \ min$,we substitute these values into the equation:$k = \frac{2.303}{30} \log_{10} (10)$.Since $\log_{10} (10) = 1$,we get:$k = \frac{2.303}{30} \approx 7.67 	imes 10^{-2} \ min^{-1}$.

Calculate the rate constant of a first-order reaction if the concentration of the reactant decreases by $90 \%$ in $30 \ minutes$.

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