Calculate the osmotic pressure of $0.5 \ M$ aqueous solution of a non-volatile solute at $300 \ K$ $\left[R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}\right]$. (in $atm$)

Calculate the molar mass of solute in a solution prepared by dissolving $1 \ g$ in $0.3 \ dm^3$ solvent having osmotic pressure $0.2 \ atm$ at $300 \ K$. $\left[R=0.082 \ dm^3 \ atm \ K^{-1} \ mol^{-1}\right]$

$A$ solution containing $10 \, g \, dm^{-3}$ of urea $(M.wt = 60)$ is isotonic with a $5 \%$ solution of a non-volatile solute. The molecular mass of this non-volatile solute is ......... $g \, mol^{-1}$.

The osmotic pressure of a solution is given by the relation

If $250 \ cm^3$ of an aqueous solution containing $0.73 \ g$ of a protein $A$ is isotonic with one litre of another aqueous solution containing $1.65 \ g$ of a protein $B,$ at $298 \ K,$ the ratio of the molecular masses of $A$ and $B$ is..........$\times 10^{-2}$ (to the nearest integer).

Calculate the amount of solute dissolved in $3 \ dm^3$ water having osmotic pressure $0.3 \ atm$ at $300 \ K$. (Molar mass of solute $= 108 \ g \ mol^{-1}, R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}$) (in $g$)