Calculate the amount of solute dissolved in 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The formula for osmotic pressure is $\pi = CRT$,where $C = \frac{n}{V} = \frac{W}{M 	imes V}$.Given: $\pi = 0.3 \ atm$,$V = 3 \ dm^3$,$T = 300 \

Vedclass · Accepted Answer

$3.95$

Vedclass · Answer

(B) The formula for osmotic pressure is $\pi = CRT$,where $C = \frac{n}{V} = \frac{W}{M 	imes V}$.Given: $\pi = 0.3 \ atm$,$V = 3 \ dm^3$,$T = 300 \ K$,$M = 108 \ g \ mol^{-1}$,$R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}$.Substituting the values: $0.3 = \frac{W}{108 	imes 3} 	imes 0.0821 	imes 300$.$0.3 = \frac{W 	imes 0.0821 	imes 300}{324}$.$W = \frac{0.3 	imes 324}{0.0821 	imes 300} = \frac{97.2}{24.63} \approx 3.946 \ g \approx 3.95 \ g$.

Calculate the amount of solute dissolved in $3 \ dm^3$ water having osmotic pressure $0.3 \ atm$ at $300 \ K$. (Molar mass of solute $= 108 \ g \ mol^{-1}, R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}$) (in $g$)

Similar Questions

What is edema?

Determine the amount of $CaCl_2$ $(i=2.47)$ dissolved in $2.5 \ L$ of water such that its osmotic pressure is $0.75 \ atm$ at $27^{\circ}C$.

What is osmotic pressure? Explain and derive its equation.

What would happen if a thin slice of sugar beet is placed in a concentrated solution of $NaCl$?

Explain reverse osmosis and the purification of water.

Vedclass Test Series

Exam Paper Generator

Online Exam Module