Calculate the number of electrons that would flow per second through the cross$-$section of a wire when $1 \,A$ current flows in it.
Here, $I =1 A , t=1 s$
$\therefore \quad Q=I \times t=1 A \times 1 s$
$=1 C$
Number of electrons $=\frac{1 C }{1.6 \times 10^{-19} C }$
$=0.625 \times 10^{19}$
$=6.25 \times 10^{18}$
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