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(B) The circuit consists of two parallel branches connected between points $A$ and $B$.Branch $1$ consists of resistors $R_1$ and $R_2$ in series: $R_

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$2$

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(B) The circuit consists of two parallel branches connected between points $A$ and $B$.Branch $1$ consists of resistors $R_1$ and $R_2$ in series: $R_{s1} = R_1 + R_2 = 3 \ \Omega + 3 \ \Omega = 6 \ \Omega$.Branch $2$ consists of resistors $R_3$ and $R_4$ in series: $R_{s2} = R_3 + R_4 = 3 \ \Omega + 3 \ \Omega = 6 \ \Omega$.Branch $3$ consists of resistor $R_5$ connected directly between $A$ and $B$: $R_5 = 6 \ \Omega$.Now,these three branches ($R_{s1}$,$R_{s2}$,and $R_5$) are connected in parallel.The equivalent resistance $R_{eq}$ is given by: $\frac{1}{R_{eq}} = \frac{1}{R_{s1}} + \frac{1}{R_{s2}} + \frac{1}{R_5}$.Substituting the values: $\frac{1}{R_{eq}} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$.Therefore,$R_{eq} = 2 \ \Omega$.

What is the equivalent resistance between points $A$ and $B$ in the given electrical circuit (in $Omega$)?

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